QUOTE(Superlatanium @ Dec 28 2016, 15:27)

This is a competition between 4 characters.
(IMG:[
reasoningtheory.net]
http://reasoningtheory.net/chars.png)
Akatsuki (Log Horizon)
Kurisu Makise (Steins;Gate)
Saber (Fate)
Ange Ushiromiya (Umineko no Naku Koro ni)
Everyone who wants to play can choose one character to support. Each supporter will add 3 fighters to that character's army.
Once time runs out, I will run a program that repeatedly chooses 2 random fighters to fight against each other.
One will win and remain, the other will be removed. (50% chance to win or to lose)
(if the random fighters are from the same army, they won't fight)
The last character with an army left wins! Everyone that supported that character will share the 2m prize equally.
PM me your chosen character, do not post it here!(IMG:[reasoningtheory.net] https://reasoningtheory.net/countdown.png?title=Character%20competition&month=1&day=03&year=2017&hour=6&minute=00)
If you want to win, I will give you some hints. Another user mentioned a useful key phrase earlier in this thread.
Also,
most of what you need to know you can find nearby; this game is probably solvable.
(the characters previously posted by users have nothing to do with this at all)
Bonus: If you explain your choice well in your PM and your character wins, you will get an extra 150k from my own pocket! (in addition to the 2m pool)
Please do not discuss or talk about the game until it's over, thanks! (IMG:[
invalid]
style_emoticons/default/smile.gif) (unless you're asking for clarification on something)
Intuitively, this original problem A could be viewed as problem B:
Who is the most popular character among the four?In this post, I'll propose a method to solve problem B. Let's get started!
MethodFirst, create a query for every character. A query is composed of two parts: name of the character and the parody, where each part is double-quoted (in order to do exact search).
For example, the query for Akatsuki would be
"Akatsuki" "Log Horizon".
Second, calculate the score of each query. A score is equal to 1/1*Score_Google + 1/33*Score_Bing + 1/266*Score_AOL. (1, 33 and 266 are global ranks of these search engines, respectively)
Score_Google = this query's search result count from Google / (sum of all query's search result counts from Google)
Score_Bing = this query's search result count from Bing / (sum of all query's search result counts from Bing)
Score_AOL = this query's search result count from AOL / (sum of all query's search result counts from AOL)
Last, choose the query with the max score, and the answer is the character in that query.
Query:
"Akatsuki" "Log Horizon"---
Google search result count: 405,000
Bing search result count: 45,600
AOL search result count: 322,000
---
Normalization WRT Google: 405000/(405000+156000+567000+29200) = 0.349982716902869
Normalization WRT Bing: 45600/(45600+17700+803000+4070) = 0.052391511655962404
Normalization WRT AOL: 322000/(322000+54400+151000+231000) = 0.42457805907172996
---
Score = 1/1*0.349982716902869 + 1/33*0.052391511655962404 + 1/266*0.42457805907172996 =
0.3531664965850122Query:
"Kurisu Makise" "Steins;Gate"---
Google search result count: 156,000
Bing search result count: 17,700
AOL search result count: 54,400
---
Normalization WRT Google: 156000/(405000+156000+567000+29200) = 0.13480815762184584
Normalization WRT Bing: 17700/(45600+17700+803000+4070) = 0.020336178866459092
Normalization WRT AOL: 54400/(322000+54400+151000+231000) = 0.07172995780590717
---
Score = 1/1*0.13480815762184584 + 1/33*0.020336178866459092 + 1/266*0.07172995780590717 =
0.13569406696179492Query:
"Saber" "Fate"---
Google search result count: 567,000
Bing search result count: 803,000
AOL search result count: 151,000
---
Normalization WRT Google: 567000/(405000+156000+567000+29200) = 0.4899758036640166
Normalization WRT Bing: 803000/(45600+17700+803000+4070) = 0.922596137274952
Normalization WRT AOL: 151000/(322000+54400+151000+231000) = 0.19910337552742616
---
Score = 1/1*0.4899758036640166 + 1/33*0.922596137274952 + 1/266*0.19910337552742616 =
0.5186817712998724Query:
"Ange Ushiromiya" "Umineko no Naku Koro ni"---
Google search result count: 29,200
Bing search result count: 4,070
AOL search result count: 231,000
---
Normalization WRT Google: 29200/(405000+156000+567000+29200) = 0.02523332181126858
Normalization WRT Bing: 4070/(45600+17700+803000+4070) = 0.0046761722026264696
Normalization WRT AOL: 231000/(322000+54400+151000+231000) = 0.3045886075949367
---
Score = 1/1*0.02523332181126858 + 1/33*0.0046761722026264696 + 1/266*0.3045886075949367 =
0.026520093952591382Since the query
"Saber" "Fate" gets the highest score (
0.5186817712998724), the answer to the problem using the proposed method is
Saber.
This post has been edited by djackallstar: Jan 3 2017, 07:35